Equation With Fraction Archives

SOLUTION OF PROBLEMS ON SIMPLE ALGEBRAIC EQUATION Solving equation by balance method Equation with bracket Equation with fraction. Solving Equation by Balance Method To solve an equation means to find the values of the unknown in the equation that makes it true. For example: 2x 9 15. 2x 9 is on the left hand side (LHS) and 15 is on the right hand side (RHS) of the equals signs. Worked examples solve 3x 12 2x 9 15. Solution 1.3x 12 Divide both sides by 3 3x 12 3 3 x 4. 2x 9 5 add 9 to both sides since +9 is the additive inverse of (-9) 2x 9 + 9 15 + 9 2x 24 x 24/2 12 EVALUATION Use the balance method to solve the following (a) 3x 8 10 (b) 20 9x + 11 (c ) 10y 7 27 (d) 9 + 2x 16. Equation with bracket Worked example solve 3(3x 1) 4 ( x + 3) Solve 5 ( x + 11) + 2 ( 2x 5) 0 Soluton 3 (3x 1) 4 ( x + 3) 9x - 3 4x + 12 Collect like terms: 9x 4x 12 + 3 5x 15 x 15/3 x 3 5 (x + 11) + 2 ( 2x 5) 0 5x + 55 + 4x 10 0 collect like terms 5x + 5x 10 55 9x -45 x -45/9 x -5. EVALUATION Solve the following : 2 (x + 5) 18 2. 6 (2s 7) 5s 3. 3x + 1 2(3x+5) 8 (2d 3) 3 (4d 7) 5. (y + 8 ) + 2 (y + 1) 0. Equation with Fraction Before collecting like terms in a equation always clear the fraction. To clear fraction, multiply both sides of the equation by the L.C. M. of the denominators of the fraction. Worked examples Solve the equations. 4m - 2m 4 5 3 3x 2 - 2x + 7 0 6 9 Solution 4m - 2m 4 5 3 LCM of 5 and 3 is 15. Multiply both sides by 15 15 x 4m - 15 x 2m 15 x 4 5 3 3 x 4m - 5 x 2m 60 12m 10m 60 2m 60 m 60 2 m 30. 3x 2 - 2x + 7 0 6 9 The LCM of 6 & 9 is 18. multiply both sides by 18 18 x (3x 2) - 18 (2x + 7 ) 0 6 9 3(3x 2) - 2 (2x + 7) 0 9x 6 - 4 x 14 0 9x 4x 14+ 6 5x 20 x 20/5 x 4. EVALUATION Solve the following equation 7a - 21 0 2. x 2 4 2 3 6m 3 2m+ 1 4. x - x 2 7 7 2 3 WEEKEND ASSIGNMENT Solve 3x + 9 117 (a) 38 (b) 36 (c) -36 (d) -38 If -2r 18 what is 4? (a) -9 (b) 20 (c) 9 (d) -20 solve 2 (x + 5) 16 (a) 13 (b) 10 (c) 8 (d) 3 Solve x 5 (a) -15 (b) 15 (c) 10 (d) -10 3 If ½ What is x? (a) 2 ½ (b) 2 2/3 (c) -2 ½ (d ) 2. THEORY Solve the following (a) 4 (x + 2) 2 (3x 1) (b) 19y -2 (6y + 1) 8 Solve the following: (a) 5e 1/4 - 7e + 4/8 0 (b) 2a 1/3 - a + 5/4 ½